Jenny De Cesarei - Italian dub actor. Article “Jenny De Cesarei” in Italian Wikipedia has 37.3 points for quality (as of July 1, 2025). The article contains 42 references and 10 sections.
In June 2025 the article “Jenny De Cesarei” was edited by 4 authors in Italian Wikipedia (4420th place) and written by 4 authors in all languages.
Since the creation of article “Jenny De Cesarei”, its content was written by 63 registered users of Italian Wikipedia and edited by 63 registered Wikipedia users in all languages.
The article is cited 217 times in Italian Wikipedia and cited 217 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Italian: #47144 07.2014 |
Global: #981953 07.2014 |
| Best Rank | Italian: #3477 11.2023 |
Global: #196837 11.2023 |
On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.
In Italian Wikipedia the most popular articles on that day were: Premi Oscar 2026, Una battaglia dopo l'altra, Michael B. Jordan, I peccatori, Andrea Kimi Antonelli, Jessie Buckley, Sean Penn, Paul Thomas Anderson, Amy Madigan, Hamnet - Nel nome del figlio.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(17.97+24.85+0+43.48+100)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
